This vignette describes various ways of summarizing
emmGrid
objects.
summary()
, confint()
, and
test()
The most important method for emmGrid
objects is
summary()
. For one thing, it is called by default when you
display an emmeans()
result. The summary()
function has a lot of options, and the detailed documentation via
help("summary.emmGrid")
is worth a look.
For ongoing illustrations, let’s re-create some of the objects in the
“basics” vignette for the pigs
example:
pigs.lm1 <- lm(log(conc) ~ source + factor(percent), data = pigs)
pigs.rg <- ref_grid(pigs.lm1)
pigs.emm.s <- emmeans(pigs.rg, "source")
Just summary(<object>)
by itself will produce a
summary that varies somewhat according to context. It does this by
setting different defaults for the infer
argument, which
consists of two logical values, specifying confidence intervals and
tests, respectively. [The exception is models fitted using MCMC methods,
where summary()
is diverted to the
hpd.summary()
function, a preferable summary for many
Bayesians.]
The summary of a newly made reference grid will show just estimates
and standard errors, but not confidence intervals or tests (that is,
infer = c(FALSE, FALSE)
). The summary of an
emmeans()
result, as we see above, will have intervals, but
no tests (i.e., infer = c(TRUE, FALSE)
); and the result of
a contrast()
call (see comparisons and contrasts) will show test
statistics and P values, but not intervals (i.e.,
infer = c(FALSE, TRUE)
). There are courtesy methods
confint()
and test()
that just call
summary()
with the appropriate infer
setting;
for example,
test(pigs.emm.s)
## source emmean SE df t.ratio p.value
## fish 3.39 0.0367 23 92.540 <.0001
## soy 3.67 0.0374 23 97.929 <.0001
## skim 3.80 0.0394 23 96.407 <.0001
##
## Results are averaged over the levels of: percent
## Results are given on the log (not the response) scale.
It is not particularly useful, though, to test these EMMs against the default of zero – which is why tests are not usually shown. It makes a lot more sense to test them against some target concentration, say 40. And suppose we want to do a one-sided test to see if the concentration is greater than 40. Remembering that the response is log-transformed in this model,
test(pigs.emm.s, null = log(40), side = ">")
## source emmean SE df null t.ratio p.value
## fish 3.39 0.0367 23 3.69 -8.026 1.0000
## soy 3.67 0.0374 23 3.69 -0.577 0.7153
## skim 3.80 0.0394 23 3.69 2.740 0.0058
##
## Results are averaged over the levels of: percent
## Results are given on the log (not the response) scale.
## P values are right-tailed
It is also possible to add calculated columns to the summary, via the
calc
argument. The calculations can include any columns up
through df
in the summary, as well as any variable in the
object’s grid
slot. Among the latter are usually weights in
a column named .wgt.
, and we can use that to include sample
size in the summary:
confint(pigs.emm.s, calc = c(n = ~.wgt.))
## source emmean SE df n lower.CL upper.CL
## fish 3.39 0.0367 23 10 3.32 3.47
## soy 3.67 0.0374 23 10 3.59 3.74
## skim 3.80 0.0394 23 9 3.72 3.88
##
## Results are averaged over the levels of: percent
## Results are given on the log (not the response) scale.
## Confidence level used: 0.95
Transformations and link functions are supported an several ways in
emmeans, making this a complex topic worthy of its own vignette. Here, we show just the
most basic approach. Namely, specifying the argument
type = "response"
will cause the displayed results to be
back-transformed to the response scale, when a transformation or link
function is incorporated in the model. For example, let’s try the
preceding test()
call again:
test(pigs.emm.s, null = log(40), side = ">", type = "response")
## source response SE df null t.ratio p.value
## fish 29.8 1.09 23 40 -8.026 1.0000
## soy 39.1 1.47 23 40 -0.577 0.7153
## skim 44.6 1.75 23 40 2.740 0.0058
##
## Results are averaged over the levels of: percent
## P values are right-tailed
## Tests are performed on the log scale
Note what changes and what doesn’t change. In the test()
call, we still use the log of 40 as the null value;
null
must always be specified on the linear-prediction
scale, in this case the log. In the output, the displayed estimates, as
well as the null
value, are shown back-transformed. As
well, the standard errors are altered (using the delta method). However,
the t ratios and P values are identical to the
preceding results. That is, the tests themselves are still conducted on
the linear-predictor scale (as is noted in the output).
Similar statements apply to confidence intervals on the response scale:
confint(pigs.emm.s, side = ">", level = .90, type = "response")
## source response SE df lower.CL upper.CL
## fish 29.8 1.09 23 28.4 Inf
## soy 39.1 1.47 23 37.3 Inf
## skim 44.6 1.75 23 42.3 Inf
##
## Results are averaged over the levels of: percent
## Confidence level used: 0.9
## Intervals are back-transformed from the log scale
With side = ">"
, a lower confidence limit is
computed on the log scale, then that limit is back-transformed to the
response scale. (We have also illustrated how to change the confidence
level.)
Both tests and confidence intervals may be adjusted for simultaneous
inference. Such adjustments ensure that the confidence coefficient for a
whole set of intervals is at least the specified level, or to control
for multiplicity in a whole family of tests. This is done via the
adjust
argument. For ref_grid()
and
emmeans()
results, the default is
adjust = "none"
. For most contrast()
results,
adjust
is often something else, depending on what type of
contrasts are created. For example, pairwise comparisons default to
adjust = "tukey"
, i.e., the Tukey HSD method. The
summary()
function sometimes changes
adjust
if it is inappropriate. For example, with
confint(pigs.emm.s, adjust = "tukey")
## Note: adjust = "tukey" was changed to "sidak"
## because "tukey" is only appropriate for one set of pairwise comparisons
## source emmean SE df lower.CL upper.CL
## fish 3.39 0.0367 23 3.30 3.49
## soy 3.67 0.0374 23 3.57 3.76
## skim 3.80 0.0394 23 3.70 3.90
##
## Results are averaged over the levels of: percent
## Results are given on the log (not the response) scale.
## Confidence level used: 0.95
## Conf-level adjustment: sidak method for 3 estimates
the adjustment is changed to the Sidak method because the Tukey adjustment is inappropriate unless you are doing pairwise comparisons.
An adjustment method that is usually appropriate is Bonferroni;
however, it can be quite conservative. Using adjust = "mvt"
is the closest to being the “exact” all-around method “single-step”
method, as it uses the multivariate t distribution (and the
mvtnorm package) with the same covariance structure as
the estimates to determine the adjustment. However, this comes at high
computational expense as the computations are done using simulation
techniques. For a large set of tests (and especially confidence
intervals), the computational lag becomes noticeable if not
intolerable.
For tests, adjust
increases the P values over
those otherwise obtained with adjust = "none"
. Compare the
following adjusted tests with the unadjusted ones previously
computed.
test(pigs.emm.s, null = log(40), side = ">", adjust = "bonferroni")
## source emmean SE df null t.ratio p.value
## fish 3.39 0.0367 23 3.69 -8.026 1.0000
## soy 3.67 0.0374 23 3.69 -0.577 1.0000
## skim 3.80 0.0394 23 3.69 2.740 0.0175
##
## Results are averaged over the levels of: percent
## Results are given on the log (not the response) scale.
## P value adjustment: bonferroni method for 3 tests
## P values are right-tailed
Sometimes you want to break a summary down into smaller pieces; for
this purpose, the by
argument in summary()
is
useful. For example,
confint(pigs.rg, by = "source")
## source = fish:
## percent prediction SE df lower.CL upper.CL
## 9 3.22 0.0536 23 3.11 3.33
## 12 3.40 0.0493 23 3.30 3.50
## 15 3.44 0.0548 23 3.32 3.55
## 18 3.52 0.0547 23 3.41 3.63
##
## source = soy:
## percent prediction SE df lower.CL upper.CL
## 9 3.49 0.0498 23 3.39 3.60
## 12 3.67 0.0489 23 3.57 3.77
## 15 3.71 0.0507 23 3.61 3.82
## 18 3.79 0.0640 23 3.66 3.93
##
## source = skim:
## percent prediction SE df lower.CL upper.CL
## 9 3.62 0.0501 23 3.52 3.73
## 12 3.80 0.0494 23 3.70 3.90
## 15 3.84 0.0549 23 3.73 3.95
## 18 3.92 0.0646 23 3.79 4.06
##
## Results are given on the log (not the response) scale.
## Confidence level used: 0.95
If there is also an adjust
in force when by
variables are used, by default, the adjustment is made
separately on each by
group; e.g., in the above,
we would be adjusting for sets of 4 intervals, not all 12 together (but
see “cross-adjustments” below.)
There can be a by
specification in
emmeans()
(or equivalently, a |
in the
formula); and if so, it is passed on to summary()
and used
unless overridden by another by
. Here are examples, not
run:
emmeans(pigs.lm, ~ percent | source) ### same results as above
summary(.Last.value, by = percent) ### grouped the other way
Specifying by = NULL
will remove all grouping.
by
groupsAs was mentioned, each by
group is regarded as a
separate family with regards to the adjust
procedure. For
example, consider a model with interaction for the
warpbreaks
data, and construct pairwise comparisons of
tension
by wool
:
warp.lm <- lm(breaks ~ wool * tension, data = warpbreaks)
warp.pw <- pairs(emmeans(warp.lm, ~ tension | wool))
warp.pw
## wool = A:
## contrast estimate SE df t.ratio p.value
## L - M 20.556 5.16 48 3.986 0.0007
## L - H 20.000 5.16 48 3.878 0.0009
## M - H -0.556 5.16 48 -0.108 0.9936
##
## wool = B:
## contrast estimate SE df t.ratio p.value
## L - M -0.556 5.16 48 -0.108 0.9936
## L - H 9.444 5.16 48 1.831 0.1704
## M - H 10.000 5.16 48 1.939 0.1389
##
## P value adjustment: tukey method for comparing a family of 3 estimates
We have two sets of 3 comparisons, and the (default) Tukey adjustment is made separately in each group.
However, sometimes we want the multiplicity adjustment to be broader.
This broadening can be done in two ways. One is to remove the
by
variable, which then treats all results as one family.
In our example:
test(warp.pw, by = NULL, adjust = "bonferroni")
## contrast wool estimate SE df t.ratio p.value
## L - M A 20.556 5.16 48 3.986 0.0014
## L - H A 20.000 5.16 48 3.878 0.0019
## M - H A -0.556 5.16 48 -0.108 1.0000
## L - M B -0.556 5.16 48 -0.108 1.0000
## L - H B 9.444 5.16 48 1.831 0.4396
## M - H B 10.000 5.16 48 1.939 0.3504
##
## P value adjustment: bonferroni method for 6 tests
This accomplishes the goal of putting all the comparisons in one family of 6 comparisons. Note that the Tukey adjustment may not be used here because we no longer have one set of pairwise comparisons.
An alternative is to specify cross.adjust
, which
specifies an additional adjustment method to apply to corresponding sets
of within-group adjusted P values:
test(warp.pw, adjust = "tukey", cross.adjust = "bonferroni")
## wool = A:
## contrast estimate SE df t.ratio p.value
## L - M 20.556 5.16 48 3.986 0.0013
## L - H 20.000 5.16 48 3.878 0.0018
## M - H -0.556 5.16 48 -0.108 1.0000
##
## wool = B:
## contrast estimate SE df t.ratio p.value
## L - M -0.556 5.16 48 -0.108 1.0000
## L - H 9.444 5.16 48 1.831 0.3407
## M - H 10.000 5.16 48 1.939 0.2777
##
## P value adjustment: tukey method for comparing a family of 3 estimates
## Cross-group P-value adjustment: bonferroni
These adjustments are less conservative than the previous result, but
it is still a conservative adjustment to the set of 6 tests. Had we also
specified adjust = "bonferroni"
, we would have obtained the
same adjusted P values as we obtained with
by = NULL
.
There is also a simple
argument for
contrast()
that is in essence the inverse of
by
; the contrasts are run using everything except
the specified variables as by
variables. To illustrate,
let’s consider the model for pigs
that includes the
interaction (so that the levels of one factor compare differently at
levels of the other factor).
pigsint.lm <- lm(log(conc) ~ source * factor(percent), data = pigs)
pigsint.rg <- ref_grid(pigsint.lm)
contrast(pigsint.rg, "consec", simple = "percent")
## source = fish:
## contrast estimate SE df t.ratio p.value
## percent12 - percent9 0.1849 0.1061 17 1.742 0.2357
## percent15 - percent12 0.0045 0.1061 17 0.042 0.9999
## percent18 - percent15 0.0407 0.1061 17 0.383 0.9626
##
## source = soy:
## contrast estimate SE df t.ratio p.value
## percent12 - percent9 0.1412 0.0949 17 1.487 0.3593
## percent15 - percent12 -0.0102 0.0949 17 -0.108 0.9992
## percent18 - percent15 0.0895 0.1342 17 0.666 0.8572
##
## source = skim:
## contrast estimate SE df t.ratio p.value
## percent12 - percent9 0.2043 0.0949 17 2.152 0.1179
## percent15 - percent12 0.1398 0.1061 17 1.317 0.4521
## percent18 - percent15 0.1864 0.1424 17 1.309 0.4568
##
## Results are given on the log (not the response) scale.
## P value adjustment: mvt method for 3 tests
In fact, we may do all one-factor comparisons by specifying
simple = "each"
. This typically produces a lot of output,
so use it with care.
From the above, we already know how to test individual results. For pairwise comparisons (details in the “comparisons” vignette), we might do
pigs.prs.s <- pairs(pigs.emm.s)
pigs.prs.s
## contrast estimate SE df t.ratio p.value
## fish - soy -0.273 0.0529 23 -5.153 0.0001
## fish - skim -0.402 0.0542 23 -7.428 <.0001
## soy - skim -0.130 0.0530 23 -2.442 0.0570
##
## Results are averaged over the levels of: percent
## Results are given on the log (not the response) scale.
## P value adjustment: tukey method for comparing a family of 3 estimates
But suppose we want an omnibus test that all these
comparisons are zero. Easy enough, using the joint
argument
in test
(note: the joint
argument is
not available in summary()
; only in
test()
):
test(pigs.prs.s, joint = TRUE)
## df1 df2 F.ratio p.value note
## 2 23 28.849 <.0001 d
##
## d: df1 reduced due to linear dependence
Notice that there are three comparisons, but only 2 d.f. for the test, as cautioned in the message.
The test produced with joint = TRUE
is a “type III” test
(assuming the default equal weights are used to obtain the EMMs). See
more on these types of tests for higher-order effects in the “interactions” vignette section on
contrasts.
For convenience, there is also a joint_tests()
function
that performs joint tests of contrasts among each term in a model or
emmGrid
object.
joint_tests(pigsint.rg)
## model term df1 df2 F.ratio p.value
## source 2 17 30.256 <.0001
## percent 3 17 8.214 0.0013
## source:percent 6 17 0.926 0.5011
The tests of main effects are of families of contrasts; those for interaction effects are for interaction contrasts. These results are essentially the same as a “Type-III ANOVA”, but may differ in situations where there are empty cells or other non-estimability issues, or if generalizations are present such as unequal weighting. (Another distinction is that sums of squares and mean squares are not shown; that is because these really are tests of contrasts among predictions, and they may or may not correspond to model sums of squares.)
One may use by
variables with joint_tests
.
For example:
joint_tests(pigsint.rg, by = "source")
## source = fish:
## model term df1 df2 F.ratio p.value
## percent 3 17 1.712 0.2023
##
## source = soy:
## model term df1 df2 F.ratio p.value
## percent 3 17 1.290 0.3097
##
## source = skim:
## model term df1 df2 F.ratio p.value
## percent 3 17 6.676 0.0035
In some models, it is possible to specify
submodel = "type2"
, thereby obtaining something akin to a
Type II analysis of variance. See the messy-data vignette for an
example.
The delta
argument in summary()
or
test()
allows the user to specify a threshold value to use
in a test of equivalence, noninferiority, or nonsuperiority. An
equivalence test is kind of a backwards significance test, where small
P values are associated with small differences relative to a
specified threshold value delta
. The help page for
summary.emmGrid
gives the details of these tests. Suppose
in the present example, we consider two sources to be equivalent if they
are within 25% of each other. We can test this as follows:
test(pigs.prs.s, delta = log(1.25), adjust = "none")
## contrast estimate SE df t.ratio p.value
## fish - soy -0.273 0.0529 23 0.937 0.8209
## fish - skim -0.402 0.0542 23 3.308 0.9985
## soy - skim -0.130 0.0530 23 -1.765 0.0454
##
## Results are averaged over the levels of: percent
## Results are given on the log (not the response) scale.
## Statistics are tests of equivalence with a threshold of 0.22314
## P values are left-tailed
By our 25% standard, the P value is quite small for comparing soy and skim, providing statistical evidence that their difference is enough smaller than the threshold to consider them equivalent.
Graphical displays of emmGrid
objects are described in
the “basics” vignette