Herein we provide the full code to realize Figures 1 to 4 that illustrate the article describing the superb
framework (Cousineau, Goulet, & Harding, 2021). These figures are based on ficticious data sets that are provided with the package superb (dataFigure1
to dataFigure4
).
Before we begin, we need to load a few packages, including superb
of course:
## Load relevant packages
library(superb) # for superbPlot
library(ggplot2) # for all the graphic directives
library(gridExtra) # for grid.arrange
If they are not present on your computer, first upload them to your computer with install.packages("name of the package")
.
The purpose of Figure 1 is to illustrate the difference in error bars when the purpose of these measures of precision is to perform pair-wise comparisons. It is based on the data from dataFigure1
, whose columns are
head(dataFigure1)
## id grp score
## 1 1 1 117
## 2 2 1 103
## 3 3 1 113
## 4 4 1 101
## 5 5 1 104
## 6 6 1 114
where id
is just a participant identifier, grp
indicate group membership (here only group 1 and group 2), and finally, score
is the dependent variable.
The first panel on the left is based on stand-alone confidence intervals and is obtained with :
plt1a <- superbPlot(dataFigure1,
BSFactors = "grp",
variables = "score",
plotStyle = "line" )
plt1a
Note that these stand-alone error bars could have been obtained by adding the argument adjustments = list(purpose = "single")
but as it is the default value, it can be omitted.
The default theme
to ggplot
s is not very attractive. Let’s decorate the plot a bit! To that end, I collected some additional ggplot directives in a list:
ornateBS <- list(
xlab("Group"),
ylab("Attitude towards class activities"),
scale_x_discrete(labels = c("Collaborative\ngames", "Unstructured\nactivities")), #new!
coord_cartesian( ylim = c(70,130) ),
geom_hline(yintercept = 100, colour = "black", size = 0.5, linetype=2),
theme_light(base_size = 14) +
theme( plot.subtitle = element_text(size=12))
)
so that the first plot, with these ornaments and a title, is:
plt1a <- plt1a + ornateBS + labs(subtitle="(stand-alone)\n95% CI")
plt1a
The second plot is obtained in a simar fashion with just one additional argument requesting difference-adjusted confidence intervals:
plt1b <- superbPlot(dataFigure1,
BSFactors = "grp",
variables = "score",
adjustments = list(purpose = "difference"), #new!
plotStyle = "line" )
plt1b <- plt1b + ornateBS + labs(subtitle="Difference-adjusted\n95% CI")
plt1b
Finally, the raincloud plot is obtained by changing the plotStyle
argument:
plt1c <- superbPlot(dataFigure1,
BSFactors = "grp",
variables = "score",
adjustments = list(purpose = "difference"),
plotStyle = "raincloud", # new layout!
violinParams = list(fill = "green", alpha = 0.2) ) # changed color to the violin
plt1c <- plt1c + ornateBS + labs(subtitle="Difference-adjusted\n95% CI")
plt1c
All three plots are shown side-by-side with:
grid.arrange(plt1a, plt1b, plt1c, ncol=3)
and exported to a file, with, e.g.:
png(filename = "Figure1.png", width = 640, height = 320)
grid.arrange(plt1a, plt1b, plt1c, ncol=3)
dev.off()
You can change the smooth density estimator (the kernel
function) by adding to the violinParams
list the following attribute: kernel = "rectangular"
for example to have a ragged density estimator.
In the end, which error bars are correct? Remember that the golden rule of adjusted confidence intervals is to look for inclusion: for example, is the mean of the second group part of the possible results suggested by the first group’s confidence interval? yes it is in the central plot. The central plot therefore indicate an absence of signficant difference. The confidence intervals being 95%, this conclusion is statistically significant at the 5% level.
Still not convinced? Let’s do a t test (actually, a Welch test; add var.equal = TRUE
for the regular t test; Delacre, Lakens, & Leys (2017)):
t.test(dataFigure1$score[dataFigure1$grp==1],
dataFigure1$score[dataFigure1$grp==2],
)
##
## Welch Two Sample t-test
##
## data: dataFigure1$score[dataFigure1$grp == 1] and dataFigure1$score[dataFigure1$grp == 2]
## t = 1.7612, df = 47.996, p-value = 0.08458
## alternative hypothesis: true difference in means is not equal to 0
## 95 percent confidence interval:
## -0.7082323 10.7082323
## sample estimates:
## mean of x mean of y
## 105 100
There are no significant difference in these data at the .05 level, so that the error bar of a 95% confidence interval should contain the other result, as is the case in the central panel.
Finally, you could try here the Tryon’s adjustments (changing to adjustments = list(purpose = "tryon")
). However, you will notice no difference at all. Indeed, the variances are almost identical in the two groups (9.99 vs. 10.08).
Figure 2 is made in a similar fashion, and using the same decorations ornate
as above with just a different name for the variable on the horizontal axis:
ornateWS <- list(
xlab("Moment"), #different!
scale_x_discrete(labels=c("Pre\ntreatment", "Post\ntreatment")),
ylab("Statistics understanding"),
coord_cartesian( ylim = c(75,125) ),
geom_hline(yintercept = 100, colour = "black", size = 0.5, linetype=2),
theme_light(base_size = 16) +
theme( plot.subtitle = element_text(size=12))
)
The difference in the present example is that the data are from a within-subject design with two repeated measures. The dataset must be in a wide format, e.g.,
head(dataFigure2)
## id pre post
## 1 1 105 128
## 2 2 96 96
## 3 3 88 102
## 4 4 80 88
## 5 5 90 83
## 6 6 86 99
This makes the left panel:
plt2a <- superbPlot(dataFigure2,
WSFactors = "Moment(2)",
variables = c("pre","post"),
adjustments = list(purpose = "single"),
plotStyle = "line" )
plt2a <- plt2a + ornateWS + labs(subtitle="Stand-alone\n95% CI")
plt2a
… and this makes the central panel, specifying the CA
(correlation-adjusted) decorelation technique:
plt2b <- superbPlot(dataFigure2,
WSFactors = "Moment(2)",
variables = c("pre","post"),
adjustments = list(purpose = "difference", decorrelation = "CA"), #new
plotStyle = "line" )
## superb::FYI: The average correlation per group is 0.8366
plt2b <- plt2b + ornateWS + labs(subtitle="Correlation and difference-\nadjusted 95% CI")
plt2b
As seen, superbPlot
issues relevant information (indicated with FYI
messages), here the correlation.
To get a sense of the general trends in the data, we can examine the data participants per participants, joining their results with a line. As seen below, for most participants, the trend is upward, suggesting a strongly reliable effect of the moment:
plt2c <- superbPlot(dataFigure2,
WSFactors = "Moment(2)",
variables = c("pre","post"),
adjustments = list(purpose = "difference", decorrelation = "CA"),
plotStyle = "pointindividualline" ) #new
plt2c <- plt2c + ornateWS + labs(subtitle="Correlation and difference-\nadjusted 95% CI")
plt2c
Just for the exercice, we also compute the plot of the difference between the scores. To that end, we need different labels on the x-axis and a different range:
ornateWS2 <- list(
xlab("Difference"),
scale_x_discrete(labels=c("Post minus Pre\ntreatment")),
ylab("Statistics understanding"),
coord_cartesian( ylim = c(-25,+25) ),
geom_hline(yintercept = 0, colour = "black", size = 0.5, linetype=2),
theme_light(base_size = 16) +
theme( plot.subtitle = element_text(size=12))
)
We then compute the differences and make the plot:
dataFigure2$diff <- dataFigure2$post - dataFigure2$pre
plt2d <- superbPlot(dataFigure2,
WSFactor = "Moment(1)",
variables = c("diff"),
adjustments = list(purpose = "single", decorrelation = "none"),
plotStyle = "raincloud",
violinParams = list(fill = "green") ) #new
plt2d <- plt2d + ornateWS2 + labs(subtitle="95% CI \nof the difference")
plt2d
This last plot does not require decorrelation and is not adjusted for difference. Decorrelation would not do anything as diff
is a single column; difference-adjustment is inadequate here as the difference is to be compared to a fix value (namely 0, for zero improvement)
Assembling all four panels, we get:
grid.arrange(plt2a, plt2b, plt2c, plt2d, ncol=4)
… which can be exported to a file as usual:
png(filename = "Figure2.png", width = 850, height = 320)
grid.arrange(plt2a, plt2b, plt2c, plt2d, ncol=4)
dev.off()
Which error bars are depicting the significance of the result most aptly? The adjusted ones seen in the central panel, as confirmed by a t-test on paired data:
t.test(dataFigure2$pre, dataFigure2$post, paired=TRUE)
##
## Paired t-test
##
## data: dataFigure2$pre and dataFigure2$post
## t = -2.9046, df = 24, p-value = 0.007776
## alternative hypothesis: true difference in means is not equal to 0
## 95 percent confidence interval:
## -8.552864 -1.447136
## sample estimates:
## mean of the differences
## -5
The confidence interval of one moment does not include the result from the other moment, indicating a significant difference between the two moments.
The novel element in Figure 3 is the fact that the participants have been recruited by clusters of participants.
We first adapt the ornaments for this example:
ornateCRS <- list(
xlab("Group"),
ylab("Quality of policies"),
scale_x_discrete(labels=c("From various\nfields", "From the\nsame field")), #new!
coord_cartesian( ylim = c(75,125) ),
geom_hline(yintercept = 100, colour = "black", size = 0.5, linetype=2),
theme_light(base_size = 14) +
theme( plot.subtitle = element_text(size=12))
)
Then, we get an unadjusted plot as usual:
plt3a <- superbPlot(dataFigure3,
BSFactors = "grp",
variables = "VD",
adjustments = list(purpose = "single", samplingDesign = "SRS"),
plotStyle = "line" )
plt3a <- plt3a + ornateCRS + labs(subtitle="Stand-alone\n95% CI")
plt3a
Here, the option samplingDesign = "SRS"
is the default and can be omitted.
To indicate the presence of cluster-randomized sampling, the samplingDesign
option is set to "CRS"
and an additional information, clusterColumn
is indicated to identify the column containing the cluster membership information:
plt3b <- superbPlot(dataFigure3,
BSFactors = "grp",
variables = "VD",
adjustments = list(purpose = "difference", samplingDesign = "CRS"), #new
plotStyle = "line",
clusterColumn = "cluster" ) #new
## superb::FYI: The ICC1 per group are 0.491 0.204
plt3b <- plt3b + ornateCRS + labs(subtitle="Cluster and difference-\nadjusted 95% CI")
plt3b
An inspection of the distribution does not make the cluster structure evident and therefore a raincloud plot is maybe little informative in the context of cluster randomized sampling…
plt3c <- superbPlot(dataFigure3,
BSFactors = "grp",
variables = "VD",
adjustments = list(purpose = "difference", samplingDesign = "CRS"),
plotStyle = "raincloud",
violinParams = list(fill = "green", alpha = 0.2),
clusterColumn = "cluster" )
plt3c <- plt3c + ornateCRS + labs(subtitle="Cluster and difference-\nadjusted 95% CI")
Here is the complete Figure 3:
grid.arrange(plt3a, plt3b, plt3c, ncol=3)
This figure is saved as before with
png(filename = "Figure3.png", width = 640, height = 320)
grid.arrange(plt3a, plt3b, plt3c, ncol=3)
dev.off()
To make the correct t test in the present case, we need a correction factor called \(\lambda\). An easy way is the following (see Cousineau & Laurencelle, 2016 for more)
res <- t.test( dataFigure3$VD[dataFigure3$grp==1],
dataFigure3$VD[dataFigure3$grp==2],
)
# mean ICCs per group, as given by superbPlot
micc <- mean(c(0.491335, 0.203857))
# lambda from five clusters of 5 participants each
lambda <- CousineauLaurencelleLambda(c(micc, 5, 5, 5, 5, 5, 5))
tcorrected <- res$statistic / lambda
pcorrected <- 1 - pt(tcorrected, 4)
cat(paste("t-test corrected for cluster-randomized sampling: t(",
2*(dim(dataFigure3)[1]-2),") = ", round(tcorrected, 3),
", p = ", round(pcorrected, 3),"\n", sep= ""))
## t-test corrected for cluster-randomized sampling: t(96) = 1.419, p = 0.114
As seen, the proper test is returning a coherent decision with the proper error bars.
Figure 4 is an illustration of the impact of sampling among a finite population.
ornateBS <- list(
xlab(""),
ylab("Metabolic score"),
scale_x_discrete(labels=c("Response to treatment")), #new!
coord_cartesian( ylim = c(75,125) ),
geom_hline(yintercept = 100, colour = "black", size = 0.5, linetype=2),
theme_light(base_size = 16) +
theme( plot.subtitle = element_text(size=12))
)
Lets do Figure 4 (see below for each plot in a single figure).
plt4a <- superbPlot(dataFigure4,
BSFactors = "group",
variables = "score",
adjustments=list(purpose = "single", popSize = Inf),
plotStyle="line" )
plt4a <- plt4a + ornateBS + labs(subtitle="Stand-alone\n95% CI")
The option popSize = Inf
is the default; it indicates that the population is presumed of infinite size. A finite size can be given, as
plt4b <- superbPlot(dataFigure4,
BSFactors = "group",
variables = "score",
adjustments=list(purpose = "single", popSize = 50 ), # new!
plotStyle="line" )
plt4b <- plt4b + ornateBS + labs(subtitle="Population size-\nadjusted 95% CI")
We illustrate the plot along some distribution information with a violin plot:
plt4c <- superbPlot(dataFigure4,
BSFactors = "group",
variables = "score",
adjustments=list(purpose = "single", popSize = 50 ), # new!
plotStyle="pointjitterviolin",
violinParams = list(fill = "green", alpha = 0.2) )
plt4c <- plt4c + ornateBS + labs(subtitle="Population size-\nadjusted 95% CI")
Which are reunited as usual:
plt4 <- grid.arrange(plt4a, plt4b, plt4c, ncol=3)
…and saved with:
png(filename = "Figure4.png", width = 640, height = 320)
grid.arrange(plt4a, plt4b, plt4c, ncol=3)
dev.off()
The corrected t test, performed by adjusting for the proportion of the population examined (see Thompson, 2012), confirms the presence of a significant difference:
res <- t.test(dataFigure4$score, mu=100)
tcorrected <- res$statistic /sqrt(1-nrow(dataFigure4) / 50)
pcorrected <- 1-pt(tcorrected, 24)
cat(paste("t-test corrected for finite-population size: t(",
nrow(dataFigure4)-1,") = ", round(tcorrected, 3),
", p = ", round(pcorrected, 3),"\n", sep= ""))
## t-test corrected for finite-population size: t(24) = 2.644, p = 0.007